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At 4,800 female residents, that's how many rapes per year?

From the Boston Globe story about the idea that the town of Wasilla made rape victims pay to report a rape, this paragraph caught my attention:

After the Alaska Legislature banned the fees, Palin's handpicked police chief, Charlie Fannon, complained that the state's action would force the town to spend $5,000 to $14,000 a year to cover the costs. "I just don't want to see any more burden put on the taxpayer," Fannon said.

Now, supposedly the town didn't actually charge people to report rapes (by billing them for the rape kit that you'd have to use in order to actually get a rape charge to stick). That's actually not what I'm interested in, here: What I'm interested in are the rape statistics implicit in Charlie Fannon's statement.

Let's do some math. Now, I know that medical supplies and procedures are expensive under the current American medical system, so let's be conservative and assume that the real cost to the town for the billable parts of a rape kit are $200 each. That works out to between 25 and 70 reported rapes per year in the town of Wasilla, based on Fannon's cost estimates. That's in a town which might possibly have as many as 4,800 female residents, depending on whose demographic data you accept.

How does that compare with national averages?

The most recent data I could quickly find is from 1998, for a sexual assault rate (incidence of actual penetrative rape would be lower) of 34.4 per 100,000 persons. Roughly estimating, that's about .03% (math corrections welcome). With a total population of about 9,600, given 25 to 70 reported rapes per year, the town of Wasilla has a rape-rate of between about .3% and .7% -- that makes Wasilla's rape rate between 10 and 20 times higher than the national average for 1998, or about 260 to 730 per 100,000 persons.

What the hell are they smoking up there?

[Correcting my math.]

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